Eight Bit Byte Mac OS
Most likely, your input file uses a single-byte 8-bit encoding such as ISO-8859-1, frequently used to encode 'Western European' languages. Regardless of the actual market share, the most compatible version (across operating systems) of IE was 5.x, which had Mac OS 9 and Mac OS X, Unix, and most Windows versions available and supported for a short period in the late 1990s (although 4.x had a more unified codebase across versions). Assuming Snow Leopard (Mac OS X 10.6.2 - Intel), then 'long' is 64-bits with the default compiler. Specify 'g -m64' and it will likely be 64-bits on earlier versions too. How a particular host (processor, OS, etc.) handles the byte and bit order is off-topic here. In general, programming libraries handle the problem for your particular host, but that, too, is off-topic here, and you could try to ask about the programming aspect on Stack Overflow.
Table Of Content
1- Bit
- If you have two boxes, you can write a number from 0 to 99.
- If you have three boxes, you can write a number from 0 to 999.
BIT
- If you have two boxes in the base-2 system, you can write the largest number of 11 (base-2), which is equivalent to 3 in the base-10 system.
- If you have 3 boxes in base-2 system, you can write the largest number of 111 (base-2), which is equivalent to 7 in base -10 system.
Box Numbers | Maximum Number (Base-2) | Convert to Base-10 |
1 | 1 | 1 (2^1 - 1) |
2 | 11 | 3 (2^2 - 1) |
3 | 111 | 7 (2^3 - 1) |
4 | 1111 | 15 (2^4 - 1) |
5 | 11111 | 31 (2^5 - 1) |
6 | 111111 | 63 (2^6 - 1) |
7 | 1111111 | 127 (2^7 - 1) |
8 | 11111111 | 255 (2^8 - 1) |
9 | 111111111 | 511 (2^9 - 1) |
Why does the computer use base-2 system but not base-10 system?
- The reader of hard drive can realize the direction of each magnetic particle to convert it into 0 or 1 signals.
- The data to be stored on hard drive is a line of 0 or 1 signals. The recorder of hard drive relies on this signal and changes the direction of each magnetic particle accordingly. This is the principle of data storage of hard drive.
2- Byte
How Many Bytes In Bit
Why is 1 byte equal to 8 bit?
Table Of Content
1- Overview of data types
- Primitive Types
- Reference Types
Data type | Default Value | Size |
---|---|---|
boolean | false | 1 bit |
char | 'u0000' | 2 byte |
byte | 0 | 1 byte |
short | 0 | 2 byte |
int | 0 | 4 byte |
long | 0L | 8 byte |
float | 0.0f | 4 byte |
double | 0.0d | 8 byte |
- Logic type: boolean.
- Integer types: byte, short, char, int, long.
- Real number type is also called floating point: float, double.
2- byte
- If it is 0, Java considers it as + (Represent a positive number)
- If it is 1 Java considers it as - (Represent a negative number)
But wait, it is supposed to be [-128, 127], why?
Why is the smallest number of byte type in Java -128?
3- boolean
4- char
Eight Bit Byte Mac Os X
- TODO
5- short
- The smallest value is -32,768 (-2^15) and the largest value is 32,767 (2^15 -1).
- Default value is 0.
6- int
- The smallest value: -2,147,483,648 (-2^31)
- The largest value: 2,147,483,647 (2^31 -1)
- Default value: 0.
7- long
- The smallest value is -9,223,372,036,854,775,808.(-2^63)
- The largest value is 9,223,372,036,854,775,807. (2^63 -1)
- This type is used when a value pattern wider than int is necessary.
- Default value is 0L.
8- float
- The smallest value: -3.4028235 x 10^38
- The largest value:: 3.4028235 x 10^38
- Default value: 0.0f
9- double
- The smallest value: -1.7976931348623157 x 10^308
- The largest value: 1.7976931348623157 x 10^308
- Default value: 0.0d